Lösung 5

 4,52 m

 3,62 m

Traufenlänge:                                                                                                  

T_Halbkegel = r.p = 3,00. p = 9,42 m

7,50 + 3,00 + 1,00 + 8,60 + 1,00 + 3,00 + 7,50 + 12,00 = 44,42 m

 5,87 m

 4,70 m

F₁ = 12,00 - 7,50 = 4,50 m

F₂ = 3,00 + 1,00 =   4,00 m

F = 8,50 m

A = 2A_{1 +} A_{2 +} A_{3 +} 2A_{4 +} A₅

A = 2.16,65 + 37,29 + 26,43 + 2.9,05 + 17,06 = 132,78 m²

 16,95 m²

 37,29m²

A₃ = A2 – Ausfallfläche = 37,29 – 10,86 =26,43m²

10,86 m²